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The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | 1/10 (x + y) = (1/4) + (x-y)/8 x = ? | 0 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | You should know that the pressure P exerted by wind varies jointly as the area of the sail A and the cube of the winds velocity V.
In this context P varies jointally means "varies directly"
P = k A V^3 where k is a constant that we will find using the given values
when A = 2 square feet, V= 8 miles per hour and the pre... | 1 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | P = kAVยณ where k is the joint constant
P=4, V=8 and A=2 so
4=k2(8)ยณ or k= 0.009765625
We want k*4*(V)ยณ=32 and solving that we get that V = 3.134055471
I would round it to 2dp and give V= 3.13mph. | 2 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | You can start by looking at the general formula for the joint variation: p = ka V^3 where a is area and k is some constant.
You should be able to work out this formula. Once you've done so, then just sub your given information to work out k. Once you've found that, you'll have a working equation for the pressure that w... | 3 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | P = kAv^3 where k is the proportionality constant. P = 4 = 8^3k(2). Solve for k, put it into P=256k and solve for v when P=32, A=4
แ What is a simple, yet elegant solution for
What is 3 + 25 แ
520931 questions in Mathematics | 4 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | P=k*V^3* A
P = kV^3A
V = [P/(kA)]^(1/3)
When P=4 Pounds, A =2 and V= 8, so
k = (P*A/V^3 = [4*2 / 8^3] = 1/256
When P = 32 A = 4
V = [(32 / (4/256)]^(1/3) = 4^1/3*4^(1/3)= 2^(2/3) mph | 5 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | You can start by writing the relation:
P = k * A * Vยณ
Then you have to use the given info and you'll be able to calculate k. Then when you calculate k you can put P and A again to solve for V (velocity)
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To view our experts click here. We can't r... | 6 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | P is proportional to A and to V^3,
P = constant * A * V^3,
A1 = 2 ft^2, A2 = 4 ft^2.
P1 = 4 lb; P2 = 32 lb
P2 / P1 = A2 / A1 * V2 / V1 ^3
32/4 = 2V2/8^3, solve for V2
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The pressure exerted by a certain liquid at a given point is directly proportional to thedepth of the l... | 7 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | P = KAVA^3
4 = K2*64
4 = 128k
K = 1/32
so,
4 = 32*6A^3
1/2 = A^3
so,
A = 3โ1/2 = (1/4)^(2/3)
so,
P = K4A^3
P = 32(1/4)^3 = 1 pound
which does not fit the 4x6=24 sqft.
What I assume, you want to be given wind pressure given area, assuming the air velocity is a known constant.
P/A = KA'V^3
where V = 8 mph
If P/A = 32/4 =... | 8 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | You're welcome.
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A flatbed truck is carrying a heavy crate. The coefficient of static friction between the crate and the bed of the truck is 0.74. What is the maximum rate at which the truck can round a turn of radius 335m without having the crate slide if the
A 110-kg linebacker (mLA... | 9 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | 1. The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds.
Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds.ใ
2. The velocity v (m/s) ... | 10 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | The equation for wind speed can be written as P = kAV3 P1 = P2 k is constant A1A2 V13 = V23 P1/A1V13 = P2/A2V23 4/83 = 32/4V23 V = sqrt[3]{8} = 2 m/h
physics - The wind exerts a force of 285N North on a sailboat,held in posi...mathematics - The wind exerts a force of 200 N North on a sailboat , held in ...algebra1 HELP... | 11 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | You should write this equation in terms of P, not p:
P = cAV3 (note that it's a lower case v for the velocity) where c is an arbitrary constant
Since we want this for a 2 ft square sail at a wind velocity of 8 miles/hr:
P = 4 = c * 2 * 83
P/8 = 128c
c = P/1024 = 1/1024 P (I'll carry this constant in the numerator so as... | 12 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | You have 6000 yards of fencing. You have to enclose a rectangular field that borders a river, so you do not need fencing along one side. Find the dimensions of the rectangle that will give the field the largest area. Give a detailed explanation
The population of a town is increasing by 2% per year, with the current pop... | 13 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | P=kAV3
4=k(2)(8)^3
k = .03125
32=k(4)(V^3)
32=(.03125)(4)(V^3)
V^3 = 32/0.125 = 256
v= 256^(1/3) | 14 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | physics - bob, Sunday, March 13, 2016 at 11:36am
the area A of the sail is 4 square ft
42 pounds = 4 * 1 ft^2 * 8^3 mph^3 = 2604.8 * ft^2 * mph^3
2604.8 pounds = 4 * 4 ft^2 * x^3 mph^3 = 16 ft^2 * x^3 mph^3
32 / 16 = 2
x^3 = 16 * 2 / mph^3 = 32 * mph^3
x = cbrt(32) * mph = 2 * cbrt(4) * mph
cbrt means the cube root
phy... | 15 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | P= k*A*V^3 (k is a proportionality constant)
When A= 2 , P = 4 ; V =8 ; find k, then when A= 4, P=32
k= (4/2)*(8^3)=256
then P= k * 4 V^3 = 32
V^3 = 256*2 / 4
V= 4*2^(2/3) or (16sqrt(2) | 16 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | If P1 = k A1 v13, then A1/A2 = v2/v1 = P2/โ(P1) so v2 = v1 โ[P2/P1] = (8 mph) โ(8 pounds/4 pounds) (1 foot2/2 feet2) โ(32 pounds/4 pounds)
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The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | The formula of the pressure is as following
P = k A* V^3
k is a constant.
When P=4, A = 2, and v=8
4= k * 2 * (8)^3
solve this to find k, then you will know P = 32, A=4, and what is V.
I am so sorry. I have to go. Please go to any other expert for help. Thanks.
Ask your question. I hope the answer is right. Thanks. | 18 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | Pressure(P) varies jointly as the area(A) of the sail and the cube(V^3) of wind speed. | 19 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | physics: Please Help
You and a friend are going to a lake. You have a boat, your friend has 6 identical tennis balls, and you have 8 identical ping pong balls. Each of the balls is exactly the same size. How will you combine balls from your friend and yourself to create a boat that is likely to be stable? Why?ๅข | 20 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | physics (pls help)
The pressure P at the bottom of a swimming pool varies directly as the depth of the pool. If the pressure is 144 lb/ft power when the pool is 2 ft deep, find the pressure when the pool is 6 ft deep
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The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | 1. What is 5.76 taken away from 14.25? A.8.79 B.7.99 C.9.49 D.8.49 2. What is the perimeter of a triangle if the side lengths are 6.15 meters, 12.52 meters, and 8.23 meters? A.15.70 meters B.16.75 meters C.26.9 meters****? D.27.9 meters 3. You buy a 5.3 pound bag of cat
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The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | If P varies jointly as the area A of the sail and the cube of the wind velocity v, this relationship can be represented by an equation like: P=kAvยณ where k is a constant.
Since the value of k is not provided in your question, I'll have to determine k by making use of the given data (when v=8, A=2, P=4), so I have:
4=k ... | 23 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | P varies directly as V^3
P=KAxV^3
At V=8, A=2, then P=4
4=k*2*(8^3)=1024K, so
K=4/1024=1/256
So, P=(1/256)AV^3, for any A,V.
When P=32 and A=4, then
32 = (1/256)*4*V^3
V^3=256/1= 256,
V=6.35
I got the same as Ms. Sue
The pressure P on a diver can be calculated using the formula P= 1+ wh , where h is the diver's depth a... | 24 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | The wind velocity when the pressure on 4 feet of sail is 32 pounds is approximately 13 mph | 25 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | The pressure p and the volume v of a certain solid are related by 3vยฒ+pยฒvยฒ=1500 If the volume is increasing at 20cm3/min find the rate of change of the pressure when volume is 10 cmยณ.
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The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | 16.00
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The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | P=kAV^3
sub in the given information to determine K
P is 4, A is 2, and V is 8
4=k(2)(8)^3
now divide to get k and it is
now substitute into P=KA
to get 32=P
sub 32 and 4 in for the P, solve for V.
P=k(2)
P=k(4)(32)^3
You should get a similar result for k.
Then plug in the value of k into your P=kAV^3, to find the valu... | 28 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | P = KAV^3, A = 2 , P = 4 ,V = 8 K (2) (8)^3=4 ( 8)^6 =2 ,V = ? (4)v^3=2 ,V^3= 4/2 = 2 , V = 2 | 29 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | I think you have a little algebra problem.
The first step would be to create your equation
P = A * V^3
Then you would use the known variables to get a number for your first constant K1 (P / A / V^3) and you would have your second equation:
P = K1 * A * V^3
After that you can just use your given data to find the second ... | 30 |
The pressure P exerted by wind on a sail varies jointly as the area A of the sail and the cube of the winds velocity V. When the velocity is 8 miles per hour, the pressure on a sail of 2 square feet is 4 pounds. Find the wind velocity when the pressure on 4 square feet of sail is 32 pounds. | P=K*A*V^3,where k is a proportionality constant.K=P/(A*V^3).K is the same for every wind and sail.P1/P2=A1*A2/V1^3/3/V2^3.V2^3/V1^3=(P1*A2)/(P2*A1).V2^3=(P1*A2)/
(P2*A1)*V1^3=12*V1^3.12^1/3=2.288V1.
What's this? It's the third one on a worksheet. I don't know how to solve the problem, nor does my little brother who was... | 31 |
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